Cubo di un binomio
Scomporre i seguenti polinomi: 1) $\displaystyle x^3-x^2+\frac{1}{3}x-\frac{1}{27}=\left(x-\frac{1}{3}\right)^3$ 2) $\displaystyle a^3-6a^2+12a-8=(a-2)^3$ 3) $\displaystyle 27a^6-54a^4+18a^2-8=(3a^2-2)^3$ 4) $\displaystyle 0,125t^3-3t^2+24t-64=(0,5t-4)^3$ 5) $\displaystyle x^{6n}-6x^{4n}+12x^{2n}-8=(x^{2n}-2)^3$ 6)…